1. Tardigrade
  2. Question
  3. Chemistry
  4. The product Z of the following reaction is H 3 CC ≡ CH ->[2 HBr ] Z

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Q. The product $Z$ of the following reaction is
$H _{3} CC \equiv CH \ce{->[{2 HBr }]} Z$

TS EAMCET 2016

Solution:

$H _{3} CC \equiv CH \ce{->[{2 HBr }]} H_3CCBr_2CH_3$

The reaction follows Markovnikov’s addition.