Question

The product of $x^{1 / 2} \cdot x^{1 / 4} \cdot x^{1 / 8} \ldots \infty$ equals

• A. 0
• B. 1
• C. x
• D. $\infty$

Answer 1

Answer: (C)

$x^{(1 / 2+1 / 4+1 / 8+\ldots(0 \infty)}=x^{\left(\frac{1 / 2}{1-1 / 2}\right)}=x$