Question

The product obtained on reaction of $C_{2}H_{5}Cl$ with hydrogen over palladium carbon is :

• A. $C_{3}H_{8}$
• B. $C_{4}H_{10}$
• C. $C_{2}H_{6}$
• D. $C_{2}H_{4}$

Answer 1

Answer: (C)

$RX \xrightarrow [Zn/HCl or]{H_2/pd or} \underset{\text{alkane}}{RH} +HX$
$(X= Br , I ) Zn / Cu / C _{2} H _{5} OH$
$C _{2} H _{5} Cl \xrightarrow[\text{reagents}]{\text { any of the above }}\underset{\text{Ethane}}{C _{2} H _{6}}+ HCl$