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Q.
The product formed in the reaction n-hexanamide $ +B{{r}_{2}}+KOH, $ is
JamiaJamia 2012
Solution:
When amide is heated with a mixture of $ B{{r}_{2}} $ in the presence of $ NaOH $ or KOH, amine is formed which has one carbon atom less than original amide. This is called Hofmanns degradation reaction. $ Hexanamide+B{{r}_{2}}+4KOH\xrightarrow{{}}Pentanamine $ $ +{{K}_{2}}C{{O}_{3}}+2KBr+2{{H}_{2}}O $