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Q. The product formed in the following reaction is: $ C{{H}_{3}}CH(C{{H}_{3}})CH=C{{H}_{2}}+HBr $ $ \xrightarrow{{}}product: $

KEAMKEAM 2000

Solution:

The addition of HBr is according to Markownikoff s rule in this reaction. $ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-CH=C{{H}_{2}}+\overset{+\,\,\,-}{\mathop{HBr}}\,\xrightarrow{{}} $ $ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}} $