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Chemistry
The product formed during the reaction is CH ≡ CH + NaOCl stackrel0° C longrightarrow
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Q. The product formed during the reaction is $CH \equiv CH + NaOCl \stackrel{0^{\circ} C }{\longrightarrow }$
Hydrocarbons
A
1,2 - dichloroethane
23%
B
1,2 - dichloroethenal
31%
C
1,2 - dichloroethene
23%
D
1,2 - dichloroethyne
23%
Solution:
With $NaOCl$, acetylene undergoes substitution in the absence of air.
$HC \equiv CH +2 NaOCl \stackrel{0^{\circ} C }{\longrightarrow } Cl - C \equiv C - Cl +2 NaOH$