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  4. The probability that police inspector Mark will catch the thief in a day is (1/4) and the probability that he will catch a robber in a day is (1/5) and the probability that he will catch both a thief and robber in a day is (1/15) then the probability that He will catch at least 1 mischief is ?

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Q. The probability that police inspector Mark will catch the thief in a day is $\frac{1}{4}$ and the probability that he will catch a robber in a day is $\frac{1}{5}$ and the probability that he will catch both a thief and robber in a day is $\frac{1}{15}$ then the probability that He will catch at least 1 mischief is ?

Probability - Part 2

Solution:

Required probability $=\frac{1}{4}+\frac{1}{5}-\frac{1}{15}=\frac{15+12-4}{60}=\frac{23}{60}$