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Q. The principal value of $\sin ^{-1}\left\{\tan \left(-\frac{5 \pi}{4}\right)\right\}$ is

Inverse Trigonometric Functions

Solution:

$\sin ^{-1}\left\{\tan \left(-\frac{5 \pi}{4}\right)\right\}=\sin ^{-1}(-1)=-\frac{\pi}{2}$