1. Tardigrade
  2. Question
  3. Physics
  4. The primary and secondary coils of a transformer have 50 and 1500 turns, respectively. If the magnetic flux φ linked with the primary coil is given by φ=φ0+4 t, where φ is in weber, t is time in second and φ0 is a constant, then the output voltage across the secondary coil is:

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The primary and secondary coils of a transformer have $50$ and $1500$ turns, respectively. If the magnetic flux $\phi$ linked with the primary coil is given by $\phi=\phi_{0}+4 t,$ where $\phi$ is in weber, $t$ is time in second and $\phi_{0}$ is a constant, then the output voltage across the secondary coil is:

Electromagnetic Induction

Solution:

Voltage across primary coil
$V_{p}=\frac{d \phi}{d t}=\frac{d}{d t}\left(\phi_{0}+4 t\right)=4\, V$
(as $\phi_{0}=$ constant)
Also, we have
$N_{p}=50$ and $N_{s}=1500$
From relation,
$\frac{V_{s}}{V_{p}}=\frac{N_{s}}{N_{p}}$
$\Rightarrow V_{s}=V_{p} \frac{N_{s}}{N_{p}}=4\left(\frac{1500}{50}\right)$
$=120\, V$