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Q. The pressure of the gas was found to decrease from $720$ to $480\, mm$. When $5\, g$ of sample of activated charcoal was kept in a flask of one litre capacity maintained at $27^{\circ} C$. If the density of characoal is $1.25\, gm / mL$. The volume of gas adsorbed per gm of charcoal at $480\, mm$ of $Hg$ is-

Surface Chemistry

Solution:

mole adsorbed $=\frac{(720-480)}{760} \times \frac{1}{0.82 \times 300}$
$=0.0128$ mole
$\therefore $ vol. at $480\, mm\, Hg =\frac{0.0128 \times 0.082 \times 300}{\frac{480}{760}}$
$=0.498 \ell=500\, ml$
$\therefore $ Volume/$gm = \frac{500}{5} = 100\,ml$