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Q.
The practical unit of resistance is $ \Omega .1 \, \Omega $ is equal to:
AFMCAFMC 2003
Solution:
From Ohm's law we have,
$V =I R $
$\Rightarrow R =\frac{V}{I}$
where, $R$ is resistance, $V$ is voltage and $I$ is current.
Also unit of voltage is $10^{8}$ emu of potential and unit of current is $\frac{1}{10}$ emu of current.
$ \therefore R =\frac{10^{8} \text{emu of potential }}{\frac{1}{10} \text{emu of current }} $ $=10^{9}$ emu of resistance