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  4. The power of x occurring in the 7th term in the expansion of ( (4x /5) - ( 8 /5x) )9 is

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Q. The power of x occurring in the 7th term in the expansion of $(\frac {4x} {5} - \frac { 8 } {5x} )^9$ is

Binomial Theorem

Solution:

$T_{7} = T_{6+1} = \,{}^{9}C_{6}\left(\frac{4x}{5}\right)^{3}\left(- \frac{8}{5x}\right)^{6}$
Power of $x = 3 - 6 = -3$