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  4. The power of a point source is 18.75 mW. Find the intensity (in mW / m 2 ) 2.5 m away from the source.

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Q. The power of a point source is $18.75 \,mW$. Find the intensity (in $mW / m ^{2}$ ) $2.5\, m$ away from the source.

Electromagnetic Waves

Solution:

$I=\frac{P}{4 \pi r^{2}}=\frac{18.75}{4 \pi \times(2.5)^{2}}$
$=0.24 \,m\,W / m ^{2}$