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Q. The power factor of the following circuit will be

Question

NTA AbhyasNTA Abhyas 2020

Solution:

$Z=\sqrt{R^{2} + ( X_{L} - X_{c} ⁡) ^{2}}$
$\Rightarrow Z=\sqrt{( r 40 + 40 ^{2} + ( 100 - 40 ^{2}}=100\Omega $
$\Rightarrow cos \phi=\frac{R}{Z}=\frac{80}{100}=0.8$