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  4. The potentials of the two plates of capacitors are +10 V and -10 V. The charge on one of the plates is 40 C. The capacitance of the capacitor is

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Q. The potentials of the two plates of capacitors are $+10\, V$ and $-10\, V$. The charge on one of the plates is $40\, C$. The capacitance of the capacitor is

Punjab PMETPunjab PMET 2006Electrostatic Potential and Capacitance

Solution:

A capacitor is an arrangement which can store sufficient quantity of charge. Suppose, on given a charge $q$ to a conductor, the electric potential of the conductor becomes $V$. Then, capacitance of capacitor is
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$C=\frac{q}{V}$
The potential difference across the parallel plate capacitor is
$10 V -(-10 V )=20\, V$
$\therefore $ Capacitance $C=\frac{Q}{V}=\frac{40}{20}=2\, F$