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Q.
The potential to which a conductor is raised, depends on
KCETKCET 2005Electrostatic Potential and Capacitance
Solution:
Potential $V=\frac{Q}{C} $
$\Rightarrow V=\frac{Q}{\frac{A \varepsilon_{0}}{d}}$
Hence, potential depends on the amount of charge, area or geometry and size of the conductor.