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Q. The potential of hydrogen electrode having a solution of $pH =4$ at $25^{\circ} C$ is

AIIMSAIIMS 2010

Solution:

$E =E^{\circ}-\frac{0.059}{n} \log \frac{1}{\left[M^{n+}\right]}$
$=0-\frac{0.059}{1} \log \left[\frac{1}{10^{-4}}\right]$
$=-0.236\, V$