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Physics
The potential field of an electric field E=(yi+xj) is
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Q. The potential field of an electric field
$ E=(yi+xj) $ is
Jharkhand CECE
Jharkhand CECE 2011
A
$ V=-(x+y)+ $ constant
B
$ V=\text{constant} $
C
$ V=-({{x}^{2}}+{{y}^{2}})+cons\tan t $
D
$ V=-xy+\text{constant} $
Solution:
We know that $ dV=-E.dr $
$ =-(yi+xj).(idx+jdy+kdz) $
$ =-(ydx+nxdy) $
$ dv=-d(xy) $
Integrating both sides, we get
$ V=-xy+\text{constant} $