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Q.
The potential energy- position graph of a particle is shown in figure. Then particle :-
Work, Energy and Power
Solution:
$\because F =-\frac{ d U }{ dx }=0$ for equilibrium
and $\frac{ d ^{2} U }{ dx ^{2}}>0$ for minimum potential energy and stable equilibrium.
$\frac{ d ^{2} U }{ dx ^{2}}<0$ for maximum potential energy and unstable equilibrium.
