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  4. The potential energy of a system of four particles placed at the vertices of a square of side l is

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Q. The potential energy of a system of four particles placed at the vertices of a square of side $l$ is

Gravitation

Solution:

$W=-4\left(\frac{G m^{2}}{l}\right)-2\left(\frac{G m^{2}}{l \sqrt{2}}\right)$
$\Rightarrow W=-\frac{2 G m^{2}}{l}\left(2+\frac{1}{\sqrt{2}}\right)$
$=-5.41\left(\frac{G m^{2}}{l}\right)$
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