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Q. The potential difference between the terminals of a cell in open circuit is 2.2 V. With resistance of $5\,\Omega$ across the terminals of a cell, the terminal potential difference is 1.8 V. The internal resistance of the cell is

KCETKCET 2003Current Electricity

Solution:

V =$\frac{ER}{R + r} = \frac{2.2 \times 5}{5 + r} $ = 1.8 $ i.e. \, r = \frac{10}{9} \Omega$