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Q. The points $A(-4,-1), B(-2,-4), C(4,0)$ and $D(2,3)$ are the vertices of

Straight Lines

Solution:

$AB =\sqrt{4+9}=\sqrt{13} $
$ BC =\sqrt{36+16}=2 \sqrt{13} $
$CD =\sqrt{4+9}=\sqrt{13} $
$AD =\sqrt{36+16}=2 \sqrt{13} $
$ AC =\sqrt{64+1}=\sqrt{65} $
$BD =\sqrt{16+49}=\sqrt{65}$
its rectangle