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Q. The points $(4, -5, 1), (3, -4, 0), (6, -7 , 3), (7, -8,4)$ are vertices of a

Three Dimensional Geometry

Solution:

Let $A(4, -5, 1)$ and $C(6, -7, 3)$
$\therefore $ Mid point of $AC(5, -6, 2)$
$B(3, -4,0) $ and $D(7, -8,4)$, Mid point of
$BD=(5, -6, 2)$
As mid point of AC = Mid point of B D
$\therefore $ ABCD is a parallelogram