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Q. The point of intersection of the normals to the parabola $y^2 = 4x$ at the ends of its latus rectum is :

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Solution:

We know that point of intersection of the normal to the parabola $y^2 = 4ax$ at the ends of its latus rectum is $(3 a, 0)$
Hence required point of intersection $= (3,0)$