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Q. The pOH value of a solution whose hydroxide ion concentration is $6.2 \times 10^{-9}$ mol/litre is

BITSATBITSAT 2012

Solution:

$- \log (OH) = pOH; - \log \,6.2 × 10^{-9} = pOH;$
$\therefore \, pOH = 8.21$