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Q. The plot of cell potential $\left(E_{\text{cell }}\right)$ against $logQ$ may be given as,
Question
Which of the following is/are correct about the plot ?

NTA AbhyasNTA Abhyas 2020

Solution:

$E_{\text{cell }}=E_{\text{cell }}^\circ -\frac{0 . 059}{n}logQ$
Slope of line $=-\frac{0 . 059}{n}$
Intercept $=E_{\text{cell }}^\circ $