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  4. The plates of a charged condenser are connected to a voltmeter. If the plates are moved apart, the reading of voltmeter will

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Q. The plates of a charged condenser are connected to a voltmeter. If the plates are moved apart, the reading of voltmeter will

J & K CETJ & K CET 2005Electrostatic Potential and Capacitance

Solution:

$q=C V=$ constant $ \ldots$ (i)
Capacitance ( C) of a parallel plate capacitor is given by
$C=\frac{\varepsilon_{0} A}{d}$
where $A$ is area of plates and $d$ the separation between them.
From Eqs. (i) and (ii), we have
$q=\frac{\varepsilon_{0} A}{d} . V=$ constant
When plates are moved apart, $d$ increases,
hence value of $C$ decreases and in order that charge $(q)$ remains constant $V$ increases.