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Q. The $\text{pK}_{\text{a}}$ values of ionisable groups in lysine are $2.18,8.95$ and $10.79$ respectively. Find isoelectric point of lysine.

NTA AbhyasNTA Abhyas 2020Biomolecules

Solution:

$\text{Isoelectric} \, \text{point} = \frac{8.95 + 10.79}{2} = 9.87$