1. Tardigrade
  2. Question
  3. Chemistry
  4. The pK a of a weak acid, HA, is equal to the pK b of a weak base, BOH. The pH of an aqueous solution of the corresponding salt, BA, will be.

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Q. The $pK _{ a }$ of a weak acid, $HA$, is equal to the $pK _{ b }$ of a weak base, $BOH$. The $pH$ of an aqueous solution of the corresponding salt, $BA$, will be______.

Equilibrium

Solution:

The salt is of weak acid and weak base.
$\therefore pH =\frac{1}{2} pK _{ w }+\frac{1}{2} pK _{ a }-\frac{1}{2} pK _{ b }$
$=\frac{1}{2} \times 14+\frac{1}{2} \times x-\frac{1}{2} \times x$
$=7$