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  3. Physics
  4. The pitch of a screw gauge having 50 divisions on its circular scale is 1 mm. When the two jaws of the screw gauge are in contact with each other, the zero of the circular scale lies 6 division below the line of graduation. When a wire is placed between the jaws, 3 linear scale divisions are clearly visible while 31st division on the circular scale coincides with the reference line. The diameter of the wire is mm

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Q. The pitch of a screw gauge having $50$ divisions on its circular scale is $1\, mm$. When the two jaws of the screw gauge are in contact with each other, the zero of the circular scale lies $6$ division below the line of graduation. When a wire is placed between the jaws, $3$ linear scale divisions are clearly visible while $31^{st}$ division on the circular scale coincides with the reference line. The diameter of the wire is______ mm

Physical World, Units and Measurements

Solution:

$\Delta l=1\,mm$
$N = 50$ division
Zero correction $= - 6$ divisions
Diameter = Measured value + Zero correction
$=3\times1+\left(6+31\right)\times\frac{1}{50}$
$=3+0.74=3.74\,mm$