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  4. The physical quantity having the dimensions [M-1 L-3 T3 A 2] is

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Q. The physical quantity having the dimensions $[M^{-1} L^{-3} T^{3} A ^{2}] $ is

KCETKCET 2006Current Electricity

Solution:

Resistivity, $\rho=\frac{m}{n e^{2} \tau}$
$\because [\rho]=\frac{[ M ]}{\left[ L ^{-3}[ AT ]^{2}[ T ]\right.}=\left[ ML ^{3} A ^{-2} T ^{-3}\right]$
So, électrical conductivity.
$\sigma =\frac{1}{\rho} $
$[\sigma] =\frac{1}{[\rho]}=\left[ M ^{-1} L ^{-3} A ^{2} T ^{3}\right]$