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Q. The photoelectric work function of a metal is 3.3 eV. The threshold frequency for this metal is approximately

Rajasthan PMTRajasthan PMT 2011

Solution:

Given, $ f=3.3eV=3.3\times 1.6\times {{10}^{-19}}V $ We know that $ f=hv $ $ v=\frac{f}{h} $ $ v=\frac{3.3\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}=0.8\times {{10}^{15}}Hz $ $ v=8.0\times {{10}^{14}}Hz $