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  4. The photoelectric work function for a metal surface is 4.125 eV. The cut-off wavelength for this surface is

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Q. The photoelectric work function for a metal surface is $4.125\, eV$. The cut-off wavelength for this surface is

AIPMTAIPMT 1999Dual Nature of Radiation and Matter

Solution:

$\phi =hv= \frac {hc}{\lambda} $
$\Rightarrow \lambda= \frac {hc}{\phi}= \frac {1242 eV.nm}{4.125}\approx 3000 \,\mathring{A} $