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Q. The photoelectric threshold of Tungsten is $2300 \,\mathring{A}$. The energy of the electrons ejected from the surface by ultraviolet light of wavelength $1800 \,\mathring{A}$ is

Dual Nature of Radiation and Matter

Solution:

$ E_k =\frac{h c}{c}\left(\frac{1}{\lambda}-\frac{1}{\lambda_0}\right)(\text { in } eV )$
$=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{1.6 \times 10^{-19}}\left(\frac{10^{10}}{1800}-\frac{10^{10}}{2300}\right)=0.15\, eV $