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  4. The photoelectric cut-off voltage in an experiment was found to be 1.5 V. The work function for the material used in the experiment was 4.2 eV. The maximum kinetic energy of the photoelectrons that was emitted was:

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Q. The photoelectric cut-off voltage in an experiment was found to be 1.5 V. The work function for the material used in the experiment was 4.2 eV. The maximum kinetic energy of the photoelectrons that was emitted was:

KEAMKEAM 2000

Solution:

If stopping potential is $ {{V}_{0}}, $ then maximum kinetic energy of photoelectrons is given by $ Ek=eV $ Given, V= 1.5 volt $ \therefore $ $ {{E}_{k}}=1.5eV $