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  4. The phase difference between two points separated by 1 m in a wave of frequency 120 Hz is 90?. The wave velocity will be:

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Q. The phase difference between two points separated by 1 m in a wave of frequency 120 Hz is 90?. The wave velocity will be:

VMMC MedicalVMMC Medical 2002

Solution:

Here: path difference $ \Delta x=1\,m $ Phase difference $ ={{90}^{o}}=0.5\pi $ Frequency $ n=120\,Hz $ $ \therefore $ Phase difference $ \text{o }\!\!|\!\!\text{ =}\frac{2\pi }{\lambda }\times \Delta x $ or $ \lambda =\frac{2\pi \times \Delta x}{\text{o }\!\!|\!\!\text{ }}=\frac{2\pi \times 1}{0.5\pi }=4m $ Hence, wave velocity $ \upsilon =n\lambda =120\times 4=480\,m/s $