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  4. The pH value of N/10 NaOH is

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Q. The pH value of N/10 NaOH is

Equilibrium

Solution:

For $NaOH, N/10 NaOH = 0.1 M\, NaOH$
$[NaOH]=0.1\,M=10^{-1}\,M$
$[OH^{-}]=[NaOH]=10^{-1}\,M$
$[H^{+}] [OH^{-}] = 10^{-14}$
$\therefore \left[H^{+}\right]=\frac{10^{-14}}{\left[OH^{-}\right]}=\frac{10^{-14}}{1\times10^{-2}}=10^{-13}$
$pH=-log\left[H^{+}\right]=-\left(log\,10^{-13}\right)=13$