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Q. The $pH$ value of $1 \times 10^{-4} M NaOH$ solution is

Uttarkhand PMTUttarkhand PMT 2009

Solution:

$1 \times 10^{-4} M \,N a O H=1 \times 10^{-4} M\left[O H^{-}\right]$
$p O H=-\log \left[O H^{-}\right]=-\log \left(1 \times 10^{-4}\right)=4$
$p H=14-p O H=14-4=10$