Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The $pH$ of the solution containing $50\, mL$ each of $0.10 \,M$ sodium acetate and $0.01 \,M$ acetic acid is [Given $pK _{ a }$ of $\left.CH _{3} COOH =4.57\right]$

NEETNEET 2022Equilibrium

Solution:

Weak acid $\left( CH _{3} COOH \right)$ and salt of weak acid-strong base $\left( CH _{3} COONa \right)$ form an acidic buffer.
Sodium acetate $\left( CH _{3} COONa \right)=0.10 \,M$;
Acetic acid $\left( CH _{3} COOH \right)=0.01 \,M$;
$pH$ of acidic buffer solution is given by
$pH = pK _{ a }+\log \frac{[\text { Salt }]}{[\text { Acid }]} $
$=4.57+\log \left(\frac{0.1}{0.01}\right)$
$=5.57$