$CH _{3} COONa + H _{2} O \rightleftharpoons \underset{\text { Weak acid }}{ CH _{3} COOH } + \underset{\text{Strong base}}{NaOH}$
As sodium acetate is a salt of weak acid and strong base, in hydrolysis of sodium acetate the $pH$ is given by
$pH =\frac{1}{2} p K_{w}+\frac{1}{2} p K_{a}+\frac{1}{2} \log C$