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Q. The $pH$ of an aqueous solution is $6 .$ The $[ OH^- ]$ of the solution will be

Solution:

$p H=-\log \left[H^{+}\right]=6$
$\left[H^{+}\right]=10^{-6},\left[O H^{-}\right]\left[H^{+}\right]=10^{-14}$
$\left[O H^{-}\right]=\frac{10^{-14}}{10^{-6}}=10^{-8} M .$