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Q. The pH of an aqueous solution having hydroxide ion concentration as $ 1\times 10^{-5} $ is

J & K CETJ & K CET 2005

Solution:

$\left[ OH ^{-}\right]=1 \times 10^{-5}$
$p OH =-\log \left[ OH ^{-}\right]$
$=-\log \left[1 \times 10^{-5}\right]$
$p OH =5 \,pH + pOH =14$
$p H =14- pOH$
$14-5 \,pH =9$