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Q. The $ pH $ of a solution containing $ 100\, mg $ of sodium hydroxide in $ 250 \,mL $ of water is

J & K CETJ & K CET 2016Equilibrium

Solution:

Molarity of solution
$=\frac{100\times 10^{-3}\times 1000}{40\times 250}$
$=0.01\,M$
$pOH=-log[10^{-2}]=2$
$\therefore pH=14-2=12$