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  4. The pH of a mixture when a 50 mL solution of pH =1 is mixed with a 50 mL solution of pH =2 is

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Q. The $pH$ of a mixture when a $50 \,mL$ solution of $pH =1$ is mixed with a $50\, mL$ solution of $pH =2$ is

Equilibrium

Solution:

$ pH =1,\left[ H ^{+}\right]=10^{-1} M ; pH =2,\left[ H ^{+}\right]=10^{-2} M$

$ M_{1} V_{1}+M_{2} V _{2}=M_{R}\left(V_{1}+V_{2}\right)$

$\Rightarrow 10^{-1} \times 50+10^{-2} \times 50=M_{R} \times 100$

$\Rightarrow M_{R}=5.5 \times 10^{-2} M$

(Resultant molarity of $H ^{+}$ ions)

$pH =-\log \left(5.5 \times 10^{-2}\right)=1.26$