Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The pH of a buffer solution of 0.l M $NH_4OH[ pK_a = 4.0]$ and $0.1 M NH_4Cl$ is

Equilibrium

Solution:

For a basic buffer,
$pOH =pk_{b}+log \frac{\text{[Salt]}}{\text{[Base]}}$
$=4.0+log \frac{0.1}{0.1}$
$=4+log\,1=4+0=4$
$pH=14-pOH=14-4=10$