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Q. The $pH$ of a $0.1\, M$ aqueous solution of a weak acid $(HA)$ is $3$ . What is its degree of dissociation?

Equilibrium

Solution:

As $pH =3$
So $\left[ H ^{+}\right]=1 \times 10^{-3}$
$\alpha=\left[ H ^{+}\right] / C$
$=1 \times 10^{-3} / 0.1$
$=0.01$ $\alpha \%=1 \%$