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  4. The pH of 10-3M NaOH is

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Q. The pH of $ {{10}^{-3}}M\,NaOH $ is

BVP MedicalBVP Medical 2010

Solution:

$ [NaOH]={{10}^{-3}}M $ $ \therefore $ $ [O{{H}^{-}}]={{10}^{-3}}M $ or $ [{{H}^{+}}]=\frac{{{10}^{-14}}}{{{10}^{-3}}}={{10}^{-11}}M $ $ pH=-\log [{{H}^{+}}]=-\log {{10}^{-11}}=11 $