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  4. The pH of 0.5 M aqueous solution of HF (Ka = 2 × 1 0- 4) is

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Q. The pH of 0.5 M aqueous solution of $HF$ $\left(K_{a} = 2 \times 1 0^{- 4}\right)$ is

NTA AbhyasNTA Abhyas 2022

Solution:

$K_{a}=C\alpha ^{2}$
$2\times 10^{4}=0.5\times \alpha ^{2}$
$\alpha =2\times 10^{- 2}$
$\therefore \left[H^{+}\right]=C\alpha =0.5\times 2\times 10^{- 2}=10^{- 2}$
$pH=2$