1. Tardigrade
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  3. Chemistry
  4. The pH of 0.1 N NaOH solution will be:

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Q. The pH of $ 0.1\,N\,NaOH $ solution will be:

J & K CETJ & K CET 2001

Solution:

$\left[O H^{-}\right]=0.1 $
$p O H=-\log \left[O H^{-}\right]$
$=-\log [0.1] p O H=1$
$p H+p O H=14$
$ p H=14-p O H$
$=14-1=13$