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Q. The pH of 0.1 M aqueous ammonia $ ({{K}_{b}}=1.8\times {{10}^{-5}}) $ is.

Rajasthan PETRajasthan PET 2009

Solution:

The aqueous solution of ammonia is basic in nature.
$ \therefore $ $ [O{{H}^{-}}]=\sqrt{{{K}_{b}}\times C} $
$ =\sqrt{1.8\times {{10}^{-5}}}\times 0.1 $
$ =1.341\times {{10}^{-3}} $
$ pOH=-\log [O{{H}^{-}}] $
$ =-\log [1.341\times {{10}^{-3}}] $
$ =2.87 $ $ pH=14-pOH $
$ =14-2.87=11.13 $